What is factor a^4b^2c^4-16 ?

The solution to factor a^4b^2c^4-16 is (a^2bc^2+4)(a^2bc^2-4)

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factor a^4b^2c^4-16

factor

a^{4} b^{2} c^{4} - 16

(a^{2} b c^{2} + 4) (a^{2} b c^{2} - 4)

Solution steps

a^{4} b^{2} c^{4} - 16

a^{4} b^{2} c^{4} = (a^{2} b c^{2})^{2}

16 = 4^{2}

= (a^{2} b c^{2})^{2} - 4^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a^{2} b c^{2})^{2} - 4^{2} = (a^{2} b c^{2} + 4) (a^{2} b c^{2} - 4)

= (a^{2} b c^{2} + 4) (a^{2} b c^{2} - 4)

\frac{3 x - 1}{5} + \frac{x + 2}{5}

1 + 4 (2 - 3 k)

14 a^{2} + 15 ab + 4 b^{2}

20 r^{4} s - 20 r^{3} s + 5 r^{2} s

(1 - 7 n) \cdot 5

What is factor a^4b^2c^4-16 ?
The solution to factor a^4b^2c^4-16 is (a^2bc^2+4)(a^2bc^2-4)