What are the solutions to the equation 9x^2+2x+5=0 ?

The solutions to the equation 9x^2+2x+5=0 are x=-1/9+i(2sqrt(11))/9 ,x=-1/9-i(2sqrt(11))/9

Find the zeros of 9x^2+2x+5=0

The zeros of 9x^2+2x+5=0 are x=-1/9+i(2sqrt(11))/9 ,x=-1/9-i(2sqrt(11))/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} + 2 x + 5 = 0

x = - \frac{1}{9} + i \frac{2 11}{9}, x = - \frac{1}{9} - i \frac{2 11}{9}

Solution steps

9 x^{2} + 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 9 \cdot 5}{2 \cdot 9}

Simplify

2^{2} - 4 \cdot 9 \cdot 5 : 411 i

x_{1, 2} = \frac{- 2 \pm 4 11 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 2 + 4 11 i}{2 \cdot 9}, x_{2} = \frac{- 2 - 4 11 i}{2 \cdot 9}

x = \frac{- 2 + 4 11 i}{2 \cdot 9} : - \frac{1}{9} + i \frac{2 11}{9}

x = \frac{- 2 - 4 11 i}{2 \cdot 9} : - \frac{1}{9} - i \frac{2 11}{9}

The solutions to the quadratic equation are:

x = - \frac{1}{9} + i \frac{2 11}{9}, x = - \frac{1}{9} - i \frac{2 11}{9}

x - 11 = 28

(x - 1)^{2}

(62)^{2}

3 x - 30 + 2 x - 9 = 180

21 - 7 x \geq 5

What are the solutions to the equation 9x^2+2x+5=0 ?
The solutions to the equation 9x^2+2x+5=0 are x=-1/9+i(2sqrt(11))/9 ,x=-1/9-i(2sqrt(11))/9
Find the zeros of 9x^2+2x+5=0
The zeros of 9x^2+2x+5=0 are x=-1/9+i(2sqrt(11))/9 ,x=-1/9-i(2sqrt(11))/9