What is 1/x-1/(x^2+x) ?

The solution to 1/x-1/(x^2+x) is 1/(x+1)

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simplify 1/x-1/(x^2+x)

simplify

\frac{1}{x} - \frac{1}{x ^{2} + x}

\frac{1}{x + 1}

Solution steps

\frac{1}{x} - \frac{1}{x ^{2} + x}

Least Common Multiplier of

x, x^{2} + x : x (x + 1)

Adjust Fractions based on the LCM

= \frac{x + 1}{x ( x + 1 )} - \frac{1}{x ( x + 1 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{x + 1 - 1}{x ( x + 1 )}

Subtract the numbers:

1 - 1 = 0

= \frac{x}{x ( x + 1 )}

Cancel the common factor:

x

= \frac{1}{x + 1}

(5 + n) 3

lo g_{5} (2 5^{7})

\frac{2}{14 - 2}

\frac{36}{- 6}