What are the solutions to the equation (2x+5)^2=49 ?

The solutions to the equation (2x+5)^2=49 are x=1,x=-6

Find the zeros of (2x+5)^2=49

The zeros of (2x+5)^2=49 are x=1,x=-6

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(2 x + 5)^{2} = 49

x = 1, x = - 6

Solution steps

(2 x + 5)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 5 = 49 : x = 1

Solve

2 x + 5 = - 49 : x = - 6

The solutions to the quadratic equation are:

x = 1, x = - 6

(u^{5})^{\frac{7}{10}}

\frac{\frac{1}{2}}{π}

cos (arcsin (2 x))

4.9 \cdot 1 0^{- 10} = \frac{( 4 x ^{2} )}{( 1.8 ) ( 1.5 )}

- 8 n = 13

What are the solutions to the equation (2x+5)^2=49 ?
The solutions to the equation (2x+5)^2=49 are x=1,x=-6
Find the zeros of (2x+5)^2=49
The zeros of (2x+5)^2=49 are x=1,x=-6