What is (2x^2+3x+1)/(x^2-2x-3) ?

The solution to (2x^2+3x+1)/(x^2-2x-3) is (2x+1)/(x-3)

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simplify (2x^2+3x+1)/(x^2-2x-3)

simplify

\frac{2 x ^{2} + 3 x + 1}{x ^{2} - 2 x - 3}

\frac{2 x + 1}{x - 3}

Solution steps

\frac{2 x ^{2} + 3 x + 1}{x ^{2} - 2 x - 3}

Factor

2 x^{2} + 3 x + 1 : (2 x + 1) (x + 1)

= \frac{( 2 x + 1 ) ( x + 1 )}{x ^{2} - 2 x - 3}

Factor

x^{2} - 2 x - 3 : (x + 1) (x - 3)

= \frac{( 2 x + 1 ) ( x + 1 )}{( x + 1 ) ( x - 3 )}

Cancel the common factor:

x + 1

= \frac{2 x + 1}{x - 3}

- 12 - 3

3^{8} \cdot 3

(x + 9) \cdot 5

2 \frac{1}{2} + \frac{9}{10}

What is (2x^2+3x+1)/(x^2-2x-3) ?
The solution to (2x^2+3x+1)/(x^2-2x-3) is (2x+1)/(x-3)