What is ((2-i)(1+2i))/(5+2i) ?

The solution to ((2-i)(1+2i))/(5+2i) is 26/29+7/29 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((2-i)(1+2i))/(5+2i)

simplify

\frac{( 2 - i ) ( 1 + 2 i )}{5 + 2 i}

\frac{26}{29} + \frac{7}{29} i

Solution steps

\frac{( 2 - i ) ( 1 + 2 i )}{5 + 2 i}

Multiply by the conjugate

\frac{5 - 2 i}{5 - 2 i}

= \frac{( 2 - i ) ( 1 + 2 i ) ( 5 - 2 i )}{( 5 + 2 i ) ( 5 - 2 i )}

Simplify

\frac{( 2 - i ) ( 1 + 2 i ) ( 5 - 2 i )}{( 5 + 2 i ) ( 5 - 2 i )} : \frac{26 + 7 i}{29}

= \frac{26 + 7 i}{29}

Rewrite in standard complex form:

\frac{26}{29} + \frac{7}{29} i

= \frac{26}{29} + \frac{7}{29} i

18 n \cdot 98 n^{3}

9 (6 q - 5 r + 6)

\frac{s ^{3}}{t ^{3}}

(a + b + c) (a + b + c)

(x - 3)^{2} - 4 (x - 3)

What is ((2-i)(1+2i))/(5+2i) ?
The solution to ((2-i)(1+2i))/(5+2i) is 26/29+7/29 i