What are the solutions to the equation 10n^2-35=65n ?

The solutions to the equation 10n^2-35=65n are n=7,n=-1/2

Find the zeros of 10n^2-35=65n

The zeros of 10n^2-35=65n are n=7,n=-1/2

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10 n^{2} - 35 = 65 n

n = 7, n = - \frac{1}{2}

Decimal Notation

n = 7, n = - 0.5

Solution steps

10 n^{2} - 35 = 65 n

Move

65 n

to the left side

10 n^{2} - 35 - 65 n = 0

Write in the standard form

a x^{2} + b x + c = 0

10 n^{2} - 65 n - 35 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 65 ) \pm ( - 65 ) ^{2} - 4 \cdot 10 ( - 35 )}{2 \cdot 10}

(- 65)^{2} - 4 \cdot 10 (- 35) = 75

n_{1, 2} = \frac{- ( - 65 ) \pm 75}{2 \cdot 10}

Separate the solutions

n_{1} = \frac{- ( - 65 ) + 75}{2 \cdot 10}, n_{2} = \frac{- ( - 65 ) - 75}{2 \cdot 10}

n = \frac{- ( - 65 ) + 75}{2 \cdot 10} : 7

n = \frac{- ( - 65 ) - 75}{2 \cdot 10} : - \frac{1}{2}

The solutions to the quadratic equation are:

n = 7, n = - \frac{1}{2}

\frac{10 !}{2 ! 8 !}

- \frac{2}{n + 4} - \frac{n ^{2}}{n ^{2} - 16}

- 3 < 2 x - 5 \leq 1

x^{2} - 9 x

\frac{1 - 5 i}{4 + 4 i} - \frac{1}{i}

What are the solutions to the equation 10n^2-35=65n ?
The solutions to the equation 10n^2-35=65n are n=7,n=-1/2
Find the zeros of 10n^2-35=65n
The zeros of 10n^2-35=65n are n=7,n=-1/2