simplify (-4i)^{-1}

Solution

simplify

(- 4 i)^{- 1}

\frac{1}{4} i

Solution steps

(- 4 i)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(- 4 i)^{- 1} = \frac{1}{- 4 i}

= \frac{1}{- 4 i}

Multiply by the conjugate

\frac{- i}{- i}

= \frac{1 \cdot ( - i )}{- 4 i ( - i )}

Simplify

\frac{1 \cdot ( - i )}{- 4 i ( - i )} : \frac{- i}{- 4}

= \frac{- i}{- 4}

Rewrite in standard complex form:

\frac{1}{4} i

= \frac{1}{4} i

\frac{6 - - 64}{10}

(x + y)^{16}

- 2 \cdot \frac{3}{7}

(121 x^{8})^{\frac{1}{2}}