What are the solutions to the equation 2x^2+3x-6=0 ?

The solutions to the equation 2x^2+3x-6=0 are x=(-3+sqrt(57))/4 ,x=(-3-sqrt(57))/4

Find the zeros of 2x^2+3x-6=0

The zeros of 2x^2+3x-6=0 are x=(-3+sqrt(57))/4 ,x=(-3-sqrt(57))/4

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2 x^{2} + 3 x - 6 = 0

x = \frac{- 3 + 57}{4}, x = \frac{- 3 - 57}{4}

Decimal Notation

x = 1.13745 \dots, x = - 2.63745 \dots

Solution steps

2 x^{2} + 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 6) = 57

x_{1, 2} = \frac{- 3 \pm 57}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 57}{2 \cdot 2}, x_{2} = \frac{- 3 - 57}{2 \cdot 2}

x = \frac{- 3 + 57}{2 \cdot 2} : \frac{- 3 + 57}{4}

x = \frac{- 3 - 57}{2 \cdot 2} : \frac{- 3 - 57}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 57}{4}, x = \frac{- 3 - 57}{4}

\frac{7 - i}{- 1 + 3 i}

8 1^{- \frac{5}{4}}

∣ x ∣ < 9

2 v + 9 = 8 v + 21

2 (- 4 x + 2) + 5 x - 2 = - 19

What are the solutions to the equation 2x^2+3x-6=0 ?
The solutions to the equation 2x^2+3x-6=0 are x=(-3+sqrt(57))/4 ,x=(-3-sqrt(57))/4
Find the zeros of 2x^2+3x-6=0
The zeros of 2x^2+3x-6=0 are x=(-3+sqrt(57))/4 ,x=(-3-sqrt(57))/4