What is factor x^5-3x^4-x^3+7x^2-4 ?

The solution to factor x^5-3x^4-x^3+7x^2-4 is (x-1)(x+1)^2(x-2)^2

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factor x^5-3x^4-x^3+7x^2-4

factor

x^{5} - 3 x^{4} - x^{3} + 7 x^{2} - 4

(x - 1) (x + 1)^{2} (x - 2)^{2}

Solution steps

x^{5} - 3 x^{4} - x^{3} + 7 x^{2} - 4

Use the rational root theorem

= (x - 1) \frac{x ^{5} - 3 x ^{4} - x ^{3} + 7 x ^{2} - 4}{x - 1}

\frac{x ^{5} - 3 x ^{4} - x ^{3} + 7 x ^{2} - 4}{x - 1} = x^{4} - 2 x^{3} - 3 x^{2} + 4 x + 4

= (x - 1) (x^{4} - 2 x^{3} - 3 x^{2} + 4 x + 4)

Factor

x^{4} - 2 x^{3} - 3 x^{2} + 4 x + 4 : (x + 1) (x + 1) (x - 2) (x - 2)

= (x - 1) (x + 1) (x + 1) (x - 2) (x - 2)

Simplify

= (x - 1) (x + 1)^{2} (x - 2)^{2}

9 (7 k + 8) + 3 (k - 10)

3 - 23

(- 2.4) + (5.6) + (- 3) + (9)

(x - 1)^{2} + (x - 1)^{3}

\frac{( 8 x ^{3} - 1 )}{( 2 x - 1 )}

What is factor x^5-3x^4-x^3+7x^2-4 ?
The solution to factor x^5-3x^4-x^3+7x^2-4 is (x-1)(x+1)^2(x-2)^2