What is 4x^2+21x+131+(792)/(x+6) ?

The solution to 4x^2+21x+131+(792)/(x+6) is (4x^3+45x^2+257x+1578)/(x+6)

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simplify 4x^2+21x+131+(792)/(x+6)

simplify

4 x^{2} + 21 x + 131 + \frac{792}{x + 6}

\frac{4 x ^{3} + 45 x ^{2} + 257 x + 1578}{x + 6}

Solution steps

4 x^{2} + 21 x + 131 + \frac{792}{x + 6}

Convert

4 x^{2}

to fraction

: \frac{4 x ^{2} ( x + 6 )}{x + 6}

Convert

21 x

to fraction

: \frac{21 x ( x + 6 )}{x + 6}

Convert

131

to fraction

: \frac{131 ( x + 6 )}{x + 6}

= \frac{4 x ^{2} ( x + 6 )}{x + 6} + \frac{21 x ( x + 6 )}{x + 6} + \frac{131 ( x + 6 )}{x + 6} + \frac{792}{x + 6}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{4 x ^{2} ( x + 6 ) + 21 x ( x + 6 ) + 131 ( x + 6 ) + 792}{x + 6}

Simplify

4 x^{2} (x + 6) + 21 x (x + 6) + 131 (x + 6) + 792 : 4 x^{3} + 45 x^{2} + 257 x + 1578

= \frac{4 x ^{3} + 45 x ^{2} + 257 x + 1578}{x + 6}

4 x^{2} + 21 x + 131 + \frac{792}{x - 6}

\frac{7 3}{5 - 2 6}

(6^{2})^{- 2}

\frac{1}{3 + 3}

(6)^{- 4}

What is 4x^2+21x+131+(792)/(x+6) ?
The solution to 4x^2+21x+131+(792)/(x+6) is (4x^3+45x^2+257x+1578)/(x+6)