What is (3x^{-2}y^3)^{-4} ?

The solution to (3x^{-2}y^3)^{-4} is (x^8)/(81y^{12)}

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simplify (3x^{-2}y^3)^{-4}

simplify

(3 x^{- 2} y^{3})^{- 4}

\frac{x ^{8}}{81 y ^{12}}

Solution steps

(3 x^{- 2} y^{3})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(3 x^{- 2} y^{3})^{- 4} = \frac{1}{( 3 x ^{- 2} y ^{3} ) ^{4}}

= \frac{1}{( 3 x ^{- 2} y ^{3} ) ^{4}}

Simplify

(3 x^{- 2} y^{3})^{4} : \frac{81 y ^{12}}{x ^{8}}

= \frac{1}{\frac{81 y ^{12}}{x ^{8}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{8}}{81 y ^{12}}

\frac{12}{5} - \frac{3}{4} + 2

\frac{1}{1 + 3 i} + \frac{1}{1 + 8 i}

(3 m - 2)^{2}

- (x - 3)

(8 + 7 i) - (- 5 + 6 i)

What is (3x^{-2}y^3)^{-4} ?
The solution to (3x^{-2}y^3)^{-4} is (x^8)/(81y^{12)}