What is (2x^2+4x)/(x^2-x) ?

The solution to (2x^2+4x)/(x^2-x) is (2(x+2))/(x-1)

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simplify (2x^2+4x)/(x^2-x)

simplify

\frac{2 x ^{2} + 4 x}{x ^{2} - x}

\frac{2 ( x + 2 )}{x - 1}

Solution steps

\frac{2 x ^{2} + 4 x}{x ^{2} - x}

Factor

2 x^{2} + 4 x : 2 x (x + 2)

= \frac{2 x ( x + 2 )}{x ^{2} - x}

Factor

x^{2} - x : x (x - 1)

= \frac{2 x ( x + 2 )}{x ( x - 1 )}

Cancel the common factor:

x

= \frac{2 ( x + 2 )}{x - 1}

\frac{3}{8} \cdot \frac{8}{9}

3.1 \cdot 4.4 \cdot 6.3

(3 - 3 i) (- 2 + 23 i)

2 (a + h)^{2}

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