What are the solutions to the equation 3x^2-8x=-7 ?

The solutions to the equation 3x^2-8x=-7 are x= 4/3+i(sqrt(5))/3 ,x= 4/3-i(sqrt(5))/3

Find the zeros of 3x^2-8x=-7

The zeros of 3x^2-8x=-7 are x= 4/3+i(sqrt(5))/3 ,x= 4/3-i(sqrt(5))/3

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3 x^{2} - 8 x = - 7

x = \frac{4}{3} + i \frac{5}{3}, x = \frac{4}{3} - i \frac{5}{3}

Solution steps

3 x^{2} - 8 x = - 7

Move

7

to the left side

3 x^{2} - 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

(- 8)^{2} - 4 \cdot 3 \cdot 7 : 25 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 5 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 5 i}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 2 5 i}{2 \cdot 3}

x = \frac{- ( - 8 ) + 2 5 i}{2 \cdot 3} : \frac{4}{3} + i \frac{5}{3}

x = \frac{- ( - 8 ) - 2 5 i}{2 \cdot 3} : \frac{4}{3} - i \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{4}{3} + i \frac{5}{3}, x = \frac{4}{3} - i \frac{5}{3}

4 x^{3} - 5 x^{2} - 28 x + 35

5 x^{2} - 20 = 0

7 x^{2} + 5 = 0

\frac{5}{\frac{19}{6}}

\frac{2}{2}

What are the solutions to the equation 3x^2-8x=-7 ?
The solutions to the equation 3x^2-8x=-7 are x= 4/3+i(sqrt(5))/3 ,x= 4/3-i(sqrt(5))/3
Find the zeros of 3x^2-8x=-7
The zeros of 3x^2-8x=-7 are x= 4/3+i(sqrt(5))/3 ,x= 4/3-i(sqrt(5))/3