en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify i^{-35}

Solution

simplify

i^{- 35}

Solution

i

Solution steps

i^{- 35}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

i^{- 35} = \frac{1}{i ^{35}}

= \frac{1}{i ^{35}}

Simplify

i^{35} : - i

= \frac{1}{- i}

Multiply by the conjugate

\frac{- i}{- i}

= \frac{1 \cdot ( - i )}{- i ( - i )}

Simplify

\frac{1 \cdot ( - i )}{- i ( - i )} : \frac{- i}{- 1}

= \frac{- i}{- 1}

Simplify

\frac{- i}{- 1} : i

= i

Popular Examples

simplify (-3-2i)-(11+10i)simplify

(- 3 - 2 i) - (11 + 10 i)

simplify 3/8*4/5 simplify

\frac{3}{8} \cdot \frac{4}{5}

simplify (2^{-2})(4^3)simplify

(2^{- 2}) (4^{3})

factor 216p^3+125q^3 factor

216 p^{3} + 125 q^{3}

simplify sqrt((x-3)^2-8(x-3))simplify

(x - 3)^{2} - 8 (x - 3)

Frequently Asked Questions (FAQ)

What is i^{-35} ?
The solution to i^{-35} is i