What is factor 25n^2-20n+4 ?

The solution to factor 25n^2-20n+4 is (5n-2)^2

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factor 25n^2-20n+4

factor

25 n^{2} - 20 n + 4

(5 n - 2)^{2}

Solution steps

25 n^{2} - 20 n + 4

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

25 n^{2} = (5 n)^{2}

4 = 2^{2}

- 20 n = - 2 \cdot 5 n \cdot 2

= (5 n)^{2} - 2 \cdot 5 n \cdot 2 + 2^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(5 n)^{2} - 2 \cdot 5 n \cdot 2 + 2^{2} = (5 n - 2)^{2}

= (5 n - 2)^{2}

(- 2) (6) (- 1)

3^{x} + 4 \cdot 3^{x + 1}

6 (- 8)

\frac{4}{5} \cdot \frac{1}{3}

3 \frac{1}{3} + 4 \frac{1}{5}