What is (x^2+5x+4)/(x^2-3x-4) ?

The solution to (x^2+5x+4)/(x^2-3x-4) is (x+4)/(x-4)

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simplify (x^2+5x+4)/(x^2-3x-4)

simplify

\frac{x ^{2} + 5 x + 4}{x ^{2} - 3 x - 4}

\frac{x + 4}{x - 4}

Solution steps

\frac{x ^{2} + 5 x + 4}{x ^{2} - 3 x - 4}

Factor

x^{2} + 5 x + 4 : (x + 1) (x + 4)

= \frac{( x + 1 ) ( x + 4 )}{x ^{2} - 3 x - 4}

Factor

x^{2} - 3 x - 4 : (x + 1) (x - 4)

= \frac{( x + 1 ) ( x + 4 )}{( x + 1 ) ( x - 4 )}

Cancel the common factor:

x + 1

= \frac{x + 4}{x - 4}

2 7^{\frac{1}{3}} - (9 - 5^{2})

4 x y + 18 x y^{2}

\frac{4 + h - 2}{h}

24 a^{3} - 6 a^{2} + 8 a - 2

2 x^{2} y + 12 x y

What is (x^2+5x+4)/(x^2-3x-4) ?
The solution to (x^2+5x+4)/(x^2-3x-4) is (x+4)/(x-4)