What is (x+2)^2-5(x+2) ?

The solution to (x+2)^2-5(x+2) is x^2-x-6

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simplify (x+2)^2-5(x+2)

simplify

(x + 2)^{2} - 5 (x + 2)

x^{2} - x - 6

Solution steps

(x + 2)^{2} - 5 (x + 2)

Expand

(x + 2)^{2} : x^{2} + 4 x + 4

= x^{2} + 4 x + 4 - 5 (x + 2)

Expand

- 5 (x + 2) : - 5 x - 10

= x^{2} + 4 x + 4 - 5 x - 10

Group like terms

= x^{2} + 4 x - 5 x + 4 - 10

Add similar elements:

4 x - 5 x = - x

= x^{2} - x + 4 - 10

Subtract the numbers:

4 - 10 = - 6

= x^{2} - x - 6

\frac{- 16}{- 8}

26 k

3 + 3

67 - 7