What is (10x^2+3)-(9x^2+4x+1) ?

The solution to (10x^2+3)-(9x^2+4x+1) is x^2-4x+2

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simplify (10x^2+3)-(9x^2+4x+1)

simplify

(10 x^{2} + 3) - (9 x^{2} + 4 x + 1)

x^{2} - 4 x + 2

Solution steps

(10 x^{2} + 3) - (9 x^{2} + 4 x + 1)

Apply rule:

(a) = a

(10 x^{2} + 3) = 10 x^{2} + 3

= 10 x^{2} + 3 - (9 x^{2} + 4 x + 1)

Apply the distributive law:

- (a + b) = - a - b

- (9 x^{2} + 4 x + 1) = - 9 x^{2} - 4 x - 1

= 10 x^{2} + 3 - 9 x^{2} - 4 x - 1

Group like terms

= 10 x^{2} - 9 x^{2} - 4 x + 3 - 1

Add similar elements:

10 x^{2} - 9 x^{2} = x^{2}

= x^{2} - 4 x + 3 - 1

Subtract the numbers:

3 - 1 = 2

= x^{2} - 4 x + 2

\frac{x + 1}{x - 1} + \frac{1}{x}

4 (3 - 4 x)

(- 23 + 2) (3 - 5)

9 x^{6} - 25

What is (10x^2+3)-(9x^2+4x+1) ?
The solution to (10x^2+3)-(9x^2+4x+1) is x^2-4x+2