What are the solutions to the equation 3t^2-12t-15=0 ?

The solutions to the equation 3t^2-12t-15=0 are t=5,t=-1

Find the zeros of 3t^2-12t-15=0

The zeros of 3t^2-12t-15=0 are t=5,t=-1

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3 t^{2} - 12 t - 15 = 0

t = 5, t = - 1

Solution steps

3 t^{2} - 12 t - 15 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 15) = 18

t_{1, 2} = \frac{- ( - 12 ) \pm 18}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 12 ) + 18}{2 \cdot 3}, t_{2} = \frac{- ( - 12 ) - 18}{2 \cdot 3}

t = \frac{- ( - 12 ) + 18}{2 \cdot 3} : 5

t = \frac{- ( - 12 ) - 18}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

t = 5, t = - 1

y^{4} + x^{2} y^{2}

(- 2 x)^{4}

3 x^{2} + 13 x + 14

2 x^{2} - 13 x y + 15 y^{2}

12 x + 3 (x + 7) > 10 x - 24

What are the solutions to the equation 3t^2-12t-15=0 ?
The solutions to the equation 3t^2-12t-15=0 are t=5,t=-1
Find the zeros of 3t^2-12t-15=0
The zeros of 3t^2-12t-15=0 are t=5,t=-1