What are the solutions to the equation 5x^2-8x-(3x^2)/4 =0 ?

The solutions to the equation 5x^2-8x-(3x^2)/4 =0 are x= 32/17 ,x=0

Find the zeros of 5x^2-8x-(3x^2)/4 =0

The zeros of 5x^2-8x-(3x^2)/4 =0 are x= 32/17 ,x=0

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5 x^{2} - 8 x - \frac{3 x ^{2}}{4} = 0

x = \frac{32}{17}, x = 0

Solution steps

5 x^{2} - 8 x - \frac{3 x ^{2}}{4} = 0

Multiply both sides by

4

20 x^{2} - 32 x - 3 x^{2} = 0

17 x^{2} - 32 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 17 \cdot 0}{2 \cdot 17}

(- 32)^{2} - 4 \cdot 17 \cdot 0 = 32

x_{1, 2} = \frac{- ( - 32 ) \pm 32}{2 \cdot 17}

Separate the solutions

x_{1} = \frac{- ( - 32 ) + 32}{2 \cdot 17}, x_{2} = \frac{- ( - 32 ) - 32}{2 \cdot 17}

x = \frac{- ( - 32 ) + 32}{2 \cdot 17} : \frac{32}{17}

x = \frac{- ( - 32 ) - 32}{2 \cdot 17} : 0

The solutions to the quadratic equation are:

x = \frac{32}{17}, x = 0

- \frac{3}{2} + \frac{24}{20} - 1.75

lo g_{\frac{1}{5}} (4)

- 3 x - 12 < 3 x + 6

a - 4 < - 12

100 = 0.072 x + x

What are the solutions to the equation 5x^2-8x-(3x^2)/4 =0 ?
The solutions to the equation 5x^2-8x-(3x^2)/4 =0 are x= 32/17 ,x=0
Find the zeros of 5x^2-8x-(3x^2)/4 =0
The zeros of 5x^2-8x-(3x^2)/4 =0 are x= 32/17 ,x=0