What is (x^2+x-6)/(x^2-9) ?

The solution to (x^2+x-6)/(x^2-9) is (x-2)/(x-3)

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simplify (x^2+x-6)/(x^2-9)

simplify

\frac{x ^{2} + x - 6}{x ^{2} - 9}

\frac{x - 2}{x - 3}

Solution steps

\frac{x ^{2} + x - 6}{x ^{2} - 9}

Factor

x^{2} + x - 6 : (x - 2) (x + 3)

= \frac{( x - 2 ) ( x + 3 )}{x ^{2} - 9}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x - 2 ) ( x + 3 )}{( x + 3 ) ( x - 3 )}

Cancel the common factor:

x + 3

= \frac{x - 2}{x - 3}

12 x^{2} y + 12 x y^{2} + 12 x yz

∣ - 24 + 2 ∣ - 10

3 lo g_{5} (100) - 6 lo g_{5} (50)

(7 x^{3}) + (- 2 x^{3} + 8 x^{2})

1 4^{2} - 144