What is (x^2y^{-2})(x^3y)^{-2} ?

The solution to (x^2y^{-2})(x^3y)^{-2} is 1/(y^4x^4)

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simplify (x^2y^{-2})(x^3y)^{-2}

simplify

(x^{2} y^{- 2}) (x^{3} y)^{- 2}

\frac{1}{y ^{4} x ^{4}}

Solution steps

(x^{2} y^{- 2}) (x^{3} y)^{- 2}

Simplify

x^{2} y^{- 2} : \frac{x ^{2}}{y ^{2}}

= \frac{x ^{2}}{y ^{2}} (x^{3} y)^{- 2}

Simplify

(x^{3} y)^{- 2} : \frac{1}{x ^{6} y ^{2}}

= \frac{x ^{2}}{y ^{2}} \cdot \frac{1}{x ^{6} y ^{2}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x ^{2} \cdot 1}{y ^{2} x ^{6} y ^{2}}

Apply rule:

a \cdot 1 = a

x^{2} \cdot 1 = x^{2}

= \frac{x ^{2}}{y ^{2} x ^{6} y ^{2}}

Simplify

\frac{x ^{2}}{x ^{6}} : \frac{1}{x ^{4}}

= \frac{1}{y ^{2} x ^{4} y ^{2}}

Simplify

y^{2} y^{2} : y^{4}

= \frac{1}{y ^{4} x ^{4}}

(3 + 2 i) + (4 i + 6)

4 (5 x - 1) - 8 x + 11

(- 3 x + 2)^{2}

6 a - 48

\frac{( 10 - 4 i )}{( 5 + i )}

What is (x^2y^{-2})(x^3y)^{-2} ?
The solution to (x^2y^{-2})(x^3y)^{-2} is 1/(y^4x^4)