What are the solutions to the equation (x-2)(x+2)=3x ?

The solutions to the equation (x-2)(x+2)=3x are x=4,x=-1

Find the zeros of (x-2)(x+2)=3x

The zeros of (x-2)(x+2)=3x are x=4,x=-1

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(x - 2) (x + 2) = 3 x

x = 4, x = - 1

Solution steps

(x - 2) (x + 2) = 3 x

Expand

(x - 2) (x + 2) : x^{2} - 4

x^{2} - 4 = 3 x

Move

3 x

to the left side

x^{2} - 4 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 4) = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 1}

x = \frac{- ( - 3 ) + 5}{2 \cdot 1} : 4

x = \frac{- ( - 3 ) - 5}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

\frac{x ^{2} - 6 x + 8}{x ^{2} + 14 x + 49} \geq 0

- x^{2} + 10 x - 21 - (3 x - 15) \leq 0

ln ∣ 2 ∣

3 x^{4} - 432 x^{2}

12 x^{2} - 8 x

What are the solutions to the equation (x-2)(x+2)=3x ?
The solutions to the equation (x-2)(x+2)=3x are x=4,x=-1
Find the zeros of (x-2)(x+2)=3x
The zeros of (x-2)(x+2)=3x are x=4,x=-1