What is (-9)/7 \div (-8)/(10) ?

The solution to (-9)/7 \div (-8)/(10) is 45/28

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(-9)/7 \div (-8)/(10)

\frac{- 9}{7} \div \frac{- 8}{10}

\frac{45}{28}

Solution steps

\frac{- 9}{7} \div \frac{- 8}{10}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{- 9}{7} \times \frac{10}{- 8}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{9}{7} \times \frac{10}{- 8}

\frac{10}{- 8} = - \frac{5}{4}

= - \frac{9}{7} (- \frac{5}{4})

Apply rule

- (- a) = a

= \frac{9}{7} \times \frac{5}{4}

Multiply fractions:

\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}

= \frac{9 \times 5}{7 \times 4}

Multiply the numbers:

9 \times 5 = 45

= \frac{45}{7 \times 4}

Multiply the numbers:

7 \times 4 = 28

= \frac{45}{28}

63 + 628

\frac{53 x ^{6}}{13 x ^{- 7}}

\frac{15}{54}

16 \cdot 25

\frac{3}{( - \frac{5}{x} ) ^{2} - 7}