What are the solutions to the equation p^2+6p-16=0 ?

The solutions to the equation p^2+6p-16=0 are p=2,p=-8

Find the zeros of p^2+6p-16=0

The zeros of p^2+6p-16=0 are p=2,p=-8

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p^{2} + 6 p - 16 = 0

p = 2, p = - 8

Solution steps

p^{2} + 6 p - 16 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

p_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 6 + 10}{2 \cdot 1}, p_{2} = \frac{- 6 - 10}{2 \cdot 1}

p = \frac{- 6 + 10}{2 \cdot 1} : 2

p = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

p = 2, p = - 8

5 x - 12 = - 2 + 5 (x - 2)

9 x \leq - 11

\frac{x}{3} - \frac{3}{4} \leq \frac{x}{4} + 1

5 (x + 1) = 3 - 2 (5 x + 4)

- π + \frac{2 π}{3}

What are the solutions to the equation p^2+6p-16=0 ?
The solutions to the equation p^2+6p-16=0 are p=2,p=-8
Find the zeros of p^2+6p-16=0
The zeros of p^2+6p-16=0 are p=2,p=-8