What is factor 9u^2+24uv+16v^2 ?

The solution to factor 9u^2+24uv+16v^2 is (3u+4v)^2

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factor 9u^2+24uv+16v^2

factor

9 u^{2} + 24 uv + 16 v^{2}

(3 u + 4 v)^{2}

Solution steps

9 u^{2} + 24 uv + 16 v^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

9 u^{2} = (3 u)^{2}

16 v^{2} = (4 v)^{2}

24 uv = 2 \cdot 3 u \cdot 4 v

= (3 u)^{2} + 2 \cdot 3 u \cdot 4 v + (4 v)^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(3 u)^{2} + 2 \cdot 3 u \cdot 4 v + (4 v)^{2} = (3 u + 4 v)^{2}

= (3 u + 4 v)^{2}

510 + 5160

\frac{- 18}{( - 6 )}

(7 - 6 i) - (- 5 - 2 i)

3 x^{4} - 243

a^{2} x^{6} - b^{2} y^{4}

What is factor 9u^2+24uv+16v^2 ?
The solution to factor 9u^2+24uv+16v^2 is (3u+4v)^2