What is factor 2n^2+n-6 ?

The solution to factor 2n^2+n-6 is (2n-3)(n+2)

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factor 2n^2+n-6

factor

2 n^{2} + n - 6

(2 n - 3) (n + 2)

Solution steps

2 n^{2} + n - 6

Break the expression into groups

= (2 n^{2} - 3 n) + (4 n - 6)

Factor out

n

from

2 n^{2} - 3 n : n (2 n - 3)

Factor out

2

from

4 n - 6 : 2 (2 n - 3)

= n (2 n - 3) + 2 (2 n - 3)

Factor out common term

2 n - 3

= (2 n - 3) (n + 2)

(- \frac{3}{5})^{- 2}

30 v - 25 = 9 v^{2}

2^{k} + 2^{k - 1}

2 (z - 1) + 3 = 17

2 (x + 3) > - 16