What is 5(3t-4)-(t^2-2)-2t(t-3) ?

The solution to 5(3t-4)-(t^2-2)-2t(t-3) is -3t^2+21t-18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 5(3t-4)-(t^2-2)-2t(t-3)

simplify

5 (3 t - 4) - (t^{2} - 2) - 2 t (t - 3)

- 3 t^{2} + 21 t - 18

Solution steps

5 (3 t - 4) - (t^{2} - 2) - 2 t (t - 3)

Apply the distributive law:

- (a - b) = - a + b

- (t^{2} - 2) = - t^{2} + 2

= 5 (3 t - 4) - t^{2} + 2 - 2 t (t - 3)

Expand

5 (3 t - 4) : 15 t - 20

= 15 t - 20 - t^{2} + 2 - 2 t (t - 3)

Expand

- 2 t (t - 3) : - 2 t^{2} + 6 t

= 15 t - 20 - t^{2} + 2 - 2 t^{2} + 6 t

Group like terms

= - t^{2} - 2 t^{2} + 15 t + 6 t - 20 + 2

Add similar elements:

- t^{2} - 2 t^{2} = - 3 t^{2}

= - 3 t^{2} + 15 t + 6 t - 20 + 2

Add similar elements:

15 t + 6 t = 21 t

= - 3 t^{2} + 21 t - 20 + 2

Add the numbers:

- 20 + 2 = - 18

= - 3 t^{2} + 21 t - 18

a^{5} - 4 a b^{4}

- 24 + 2 (y - 9)

\frac{1}{3 - 2}

(2 x + 1) (x - 7)

\frac{5}{6} \cdot 8

What is 5(3t-4)-(t^2-2)-2t(t-3) ?
The solution to 5(3t-4)-(t^2-2)-2t(t-3) is -3t^2+21t-18