What is (35ab)/(-49a^4b^3) ?

The solution to (35ab)/(-49a^4b^3) is -5/(7a^3b^2)

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simplify (35ab)/(-49a^4b^3)

simplify

\frac{35 ab}{- 49 a ^{4} b ^{3}}

- \frac{5}{7 a ^{3} b ^{2}}

Solution steps

\frac{35 ab}{- 49 a ^{4} b ^{3}}

Factor the number:

35 = 7 \cdot 5

= \frac{7 \cdot 5 ab}{- 49 a ^{4} b ^{3}}

Factor the number:

49 = 7 \cdot 7

= \frac{7 \cdot 5 ab}{- 7 \cdot 7 a ^{4} b ^{3}}

Cancel the common factor:

7

= \frac{5 ab}{- 7 a ^{4} b ^{3}}

Simplify

\frac{a}{a ^{4}} : \frac{1}{a ^{3}}

= \frac{5 b}{- 7 a ^{3} b ^{3}}

Simplify

\frac{b}{b ^{3}} : \frac{1}{b ^{2}}

= \frac{5}{- 7 a ^{3} b ^{2}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{5}{7 a ^{3} b ^{2}}

(1 - i)^{- 1}

\frac{- 56}{- 7}

28 + 8

\frac{3 ( a - b )}{9} + \frac{4}{9} b

\frac{x}{x + 1} + \frac{1}{x}