What are the solutions to the equation x^2-4x+4=0 ?

The solutions to the equation x^2-4x+4=0 are x=2

Find the zeros of x^2-4x+4=0

The zeros of x^2-4x+4=0 are x=2

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x^{2} - 4 x + 4 = 0

x = 2

Solution steps

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

(e^{3}) (e^{- 3})

- 2 x = - 16

∣ 2 x - 6 ∣ + 10 = 12

2 (- \frac{4}{5})^{0}

(4^{- 2} \cdot 4^{- 3})^{3}

What are the solutions to the equation x^2-4x+4=0 ?
The solutions to the equation x^2-4x+4=0 are x=2
Find the zeros of x^2-4x+4=0
The zeros of x^2-4x+4=0 are x=2