What is cos(x)[cos(2x)-2sin^2(x)] ?

The solution to cos(x)[cos(2x)-2sin^2(x)] is 4cos^3(x)-3cos(x)

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simplify cos(x)[cos(2x)-2sin^2(x)]

simplify

cos (x) [cos (2 x) - 2 sin^{2} (x)]

4 cos^{3} (x) - 3 cos (x)

Solution steps

cos (x) (cos (2 x) - 2 sin^{2} (x))

Rewrite using trig identities

= (- 3 + 4 cos^{2} (x)) cos (x)

Expand

(- 3 + 4 cos^{2} (x)) cos (x) : - 3 cos (x) + 4 cos^{3} (x)

= 4 cos^{3} (x) - 3 cos (x)

\frac{15 x ^{2}}{10 x}

9 ln (e^{2})

\frac{3 ( u ) ^{3}}{5 u ^{4}}

5 x - 4 - 7 x + 14

lo g_{8} (2) + lo g_{4} (2)

What is cos(x)[cos(2x)-2sin^2(x)] ?
The solution to cos(x)[cos(2x)-2sin^2(x)] is 4cos^3(x)-3cos(x)