What is (8w^2z^{-2})^2(z^3) ?

The solution to (8w^2z^{-2})^2(z^3) is (64w^4)/z

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simplify (8w^2z^{-2})^2(z^3)

simplify

(8 w^{2} z^{- 2})^{2} (z^{3})

\frac{64 w ^{4}}{z}

Solution steps

(8 w^{2} z^{- 2})^{2} (z^{3})

Apply rule:

(a) = a

(z^{3}) = z^{3}

= (8 w^{2} z^{- 2})^{2} z^{3}

Simplify

(8 w^{2} z^{- 2})^{2} : \frac{64 w ^{4}}{z ^{4}}

= \frac{64 w ^{4}}{z ^{4}} z^{3}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{64 w ^{4} z ^{3}}{z ^{4}}

Simplify

\frac{z ^{3}}{z ^{4}} : \frac{1}{z}

= \frac{64 w ^{4}}{z}

\frac{60}{75}

7 - 8 x - 12 x - 5 + 2 x

(a + b - 1) (a^{2} + 1) - a^{2} - 1

(x^{\frac{4}{7}})^{- 7}

\frac{39}{65} \div \frac{3}{26}