What is expand (x-2)(x+2)(x^2+4) ?

The solution to expand (x-2)(x+2)(x^2+4) is x^4-16

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expand (x-2)(x+2)(x^2+4)

expand

(x - 2) (x + 2) (x^{2} + 4)

x^{4} - 16

Solution steps

(x - 2) (x + 2) (x^{2} + 4)

Expand

(x - 2) (x + 2) (x^{2} + 4) : (x^{2} - 4) (x^{2} + 4)

= (x^{2} - 4) (x^{2} + 4)

Apply Difference of Two Squares

(x^{2} - 4) (x^{2} + 4) : x^{4} - 16

= x^{4} - 16

\frac{3 x ^{3} - 3 - 6 x}{3 + 3 x}

(5 x^{2} + x - 4) (x + 2)

4 (2 x - 1)

\frac{4}{3} \cdot \frac{6}{5}

x^{3} + x^{2} y + x y^{2}

What is expand (x-2)(x+2)(x^2+4) ?
The solution to expand (x-2)(x+2)(x^2+4) is x^4-16