What are the solutions to the equation 467=-0.5x^2+36x-145 ?

The solutions to the equation 467=-0.5x^2+36x-145 are x=6(6-sqrt(2)),x=6(6+sqrt(2))

Find the zeros of 467=-0.5x^2+36x-145

The zeros of 467=-0.5x^2+36x-145 are x=6(6-sqrt(2)),x=6(6+sqrt(2))

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467 = - 0.5 x^{2} + 36 x - 145

x = 6 (6 - 2), x = 6 (6 + 2)

Solution steps

467 = - 0.5 x^{2} + 36 x - 145

Multiply both sides by

10

4670 = - 5 x^{2} + 360 x - 1450

Switch sides

- 5 x^{2} + 360 x - 1450 = 4670

Move

4670

to the left side

- 5 x^{2} + 360 x - 6120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 360 \pm 36 0 ^{2} - 4 ( - 5 ) ( - 6120 )}{2 ( - 5 )}

36 0^{2} - 4 (- 5) (- 6120) = 602

x_{1, 2} = \frac{- 360 \pm 60 2}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 360 + 60 2}{2 ( - 5 )}, x_{2} = \frac{- 360 - 60 2}{2 ( - 5 )}

x = \frac{- 360 + 60 2}{2 ( - 5 )} : 6 (6 - 2)

x = \frac{- 360 - 60 2}{2 ( - 5 )} : 6 (6 + 2)

The solutions to the quadratic equation are:

x = 6 (6 - 2), x = 6 (6 + 2)

\frac{1}{5} (- 25 + 15 a) = \frac{1}{2} (6 a - 10)

2 ∣ - 2 s + 600 ∣ - 8 = 392

22 < 6 c + 4

3 x - 4 = 5 + 3 (\frac{x}{5} - 1)

3 j + 2 = 5 j - 4

What are the solutions to the equation 467=-0.5x^2+36x-145 ?
The solutions to the equation 467=-0.5x^2+36x-145 are x=6(6-sqrt(2)),x=6(6+sqrt(2))
Find the zeros of 467=-0.5x^2+36x-145
The zeros of 467=-0.5x^2+36x-145 are x=6(6-sqrt(2)),x=6(6+sqrt(2))