What is (2x^{-1})^2(2x^0) ?

The solution to (2x^{-1})^2(2x^0) is 8/(x^2)

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simplify (2x^{-1})^2(2x^0)

simplify

(2 x^{- 1})^{2} (2 x^{0})

\frac{8}{x ^{2}}

Solution steps

(2 x^{- 1})^{2} (2 x^{0})

Simplify

(2 x^{- 1})^{2} : \frac{4}{x ^{2}}

= \frac{4}{x ^{2}} \cdot 2 x^{0}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

x^{0} = 1

= \frac{4}{x ^{2}} \cdot 2 \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= \frac{4}{x ^{2}} \cdot 2

= 2 \cdot \frac{4}{x ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 4}{x ^{2}}

Multiply the numbers:

2 \cdot 4 = 8

= \frac{8}{x ^{2}}

(7 x + 3) (x - 9)

- ∣ 4 ∣

6 \cdot (- 9)

126 - 76 + 36

3 (r - 10 t) - 4 (7 t + 2 r)