What is factor 8x^4y^5+4x^2y^4 ?

The solution to factor 8x^4y^5+4x^2y^4 is 4x^2y^4(2x^2y+1)

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factor 8x^4y^5+4x^2y^4

factor

8 x^{4} y^{5} + 4 x^{2} y^{4}

4 x^{2} y^{4} (2 x^{2} y + 1)

Solution steps

8 x^{4} y^{5} + 4 x^{2} y^{4}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{4} y^{5} = x^{2} x^{2} y^{4} y

= 8 x^{2} x^{2} y^{4} y + 4 x^{2} y^{4}

Rewrite

8

2 \cdot 4

= 2 \cdot 4 x^{2} x^{2} y^{4} y + 4 x^{2} y^{4}

Factor out common term

4 x^{2} y^{4}

= 4 x^{2} y^{4} (2 x^{2} y + 1)

\frac{- 10}{- 4}

- \frac{1}{3} \cdot (- 4)

9 (6 t - 2 v + 9)

\frac{48}{- 8}

What is factor 8x^4y^5+4x^2y^4 ?
The solution to factor 8x^4y^5+4x^2y^4 is 4x^2y^4(2x^2y+1)