What are the solutions to the equation 4x^2+5x-3=0 ?

The solutions to the equation 4x^2+5x-3=0 are x=(-5+sqrt(73))/8 ,x=(-5-sqrt(73))/8

Find the zeros of 4x^2+5x-3=0

The zeros of 4x^2+5x-3=0 are x=(-5+sqrt(73))/8 ,x=(-5-sqrt(73))/8

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4 x^{2} + 5 x - 3 = 0

x = \frac{- 5 + 73}{8}, x = \frac{- 5 - 73}{8}

Solution steps

4 x^{2} + 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 3) = 73

x_{1, 2} = \frac{- 5 \pm 73}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 73}{2 \cdot 4}, x_{2} = \frac{- 5 - 73}{2 \cdot 4}

x = \frac{- 5 + 73}{2 \cdot 4} : \frac{- 5 + 73}{8}

x = \frac{- 5 - 73}{2 \cdot 4} : \frac{- 5 - 73}{8}

The solutions to the quadratic equation are:

x = \frac{- 5 + 73}{8}, x = \frac{- 5 - 73}{8}

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What are the solutions to the equation 4x^2+5x-3=0 ?
The solutions to the equation 4x^2+5x-3=0 are x=(-5+sqrt(73))/8 ,x=(-5-sqrt(73))/8
Find the zeros of 4x^2+5x-3=0
The zeros of 4x^2+5x-3=0 are x=(-5+sqrt(73))/8 ,x=(-5-sqrt(73))/8