What is ((-2jk^2)/(3km^4))^3 ?

The solution to ((-2jk^2)/(3km^4))^3 is -(8j^3k^3)/(27m^{12)}

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simplify ((-2jk^2)/(3km^4))^3

simplify

(\frac{- 2 j k ^{2}}{3 k m ^{4}})^{3}

- \frac{8 j ^{3} k ^{3}}{27 m ^{12}}

Solution steps

(\frac{- 2 j k ^{2}}{3 k m ^{4}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( - 2 j k ^{2} ) ^{3}}{( 3 k m ^{4} ) ^{3}}

Simplify

(- 2 j k^{2})^{3} : - 8 j^{3} k^{6}

= \frac{- 8 j ^{3} k ^{6}}{( 3 k m ^{4} ) ^{3}}

Simplify

(3 k m^{4})^{3} : 27 k^{3} m^{12}

= \frac{- 8 j ^{3} k ^{6}}{27 k ^{3} m ^{12}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{8 j ^{3} k ^{6}}{27 k ^{3} m ^{12}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{k ^{6}}{k ^{3}} = k^{6 - 3}

= \frac{8 j ^{3} k ^{6 - 3}}{27 m ^{12}}

Subtract the numbers:

6 - 3 = 3

= - \frac{8 j ^{3} k ^{3}}{27 m ^{12}}

(p^{2})^{5}

\frac{3}{8} - \frac{2}{5}

(3 + 4 i)^{- 1}

- (9.2 n + p - 3.1)

What is ((-2jk^2)/(3km^4))^3 ?
The solution to ((-2jk^2)/(3km^4))^3 is -(8j^3k^3)/(27m^{12)}