What are the solutions to the equation x^2+2x-2=0 ?

The solutions to the equation x^2+2x-2=0 are x=-1+sqrt(3),x=-1-sqrt(3)

Find the zeros of x^2+2x-2=0

The zeros of x^2+2x-2=0 are x=-1+sqrt(3),x=-1-sqrt(3)

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x^{2} + 2 x - 2 = 0

x = - 1 + 3, x = - 1 - 3

Solution steps

x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 2) = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3}{2 \cdot 1}

x = \frac{- 2 + 2 3}{2 \cdot 1} : - 1 + 3

x = \frac{- 2 - 2 3}{2 \cdot 1} : - 1 - 3

The solutions to the quadratic equation are:

x = - 1 + 3, x = - 1 - 3

4 x^{2} - 12 x + 8

\frac{8}{- 2}

(\frac{3 - i 3}{3}) (\frac{2 + i 3}{3})

\frac{1}{i ^{- 14}}

lo g_{6} (\frac{1}{36}) = x

What are the solutions to the equation x^2+2x-2=0 ?
The solutions to the equation x^2+2x-2=0 are x=-1+sqrt(3),x=-1-sqrt(3)
Find the zeros of x^2+2x-2=0
The zeros of x^2+2x-2=0 are x=-1+sqrt(3),x=-1-sqrt(3)