What is factor 12x^4-20x^3+4x^2 ?

The solution to factor 12x^4-20x^3+4x^2 is 4x^2(3x^2-5x+1)

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factor 12x^4-20x^3+4x^2

factor

12 x^{4} - 20 x^{3} + 4 x^{2}

4 x^{2} (3 x^{2} - 5 x + 1)

Solution steps

12 x^{4} - 20 x^{3} + 4 x^{2}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{3} = x x^{2}

= 12 x^{2} x^{2} - 20 x x^{2} + 4 x^{2}

Rewrite

12

4 \cdot 3

Rewrite

20

4 \cdot 5

= 4 \cdot 3 x^{2} x^{2} - 4 \cdot 5 x x^{2} + 4 \cdot 1 \cdot x^{2}

Factor out common term

4 x^{2}

= 4 x^{2} (3 x^{2} - 5 x + 1)

\frac{40}{44}

10 x + 10

86 + (- 38)

\frac{32}{25}

(x - 2)^{2} + 8 (x - 2) + 5

What is factor 12x^4-20x^3+4x^2 ?
The solution to factor 12x^4-20x^3+4x^2 is 4x^2(3x^2-5x+1)