What is (4y^{-2})(8y^{-4}) ?

The solution to (4y^{-2})(8y^{-4}) is (32)/(y^6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (4y^{-2})(8y^{-4})

simplify

(4 y^{- 2}) (8 y^{- 4})

\frac{32}{y ^{6}}

Solution steps

(4 y^{- 2}) (8 y^{- 4})

Simplify

4 y^{- 2} : \frac{4}{y ^{2}}

= \frac{4}{y ^{2}} \cdot 8 y^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

y^{- 4} = \frac{1}{y ^{4}}

= \frac{4}{y ^{2}} \cdot 8 \cdot \frac{1}{y ^{4}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{4 \cdot 8 \cdot 1}{y ^{2} y ^{4}}

Multiply the numbers:

4 \cdot 8 \cdot 1 = 32

= \frac{32}{y ^{2} y ^{4}}

Simplify

y^{2} y^{4} : y^{6}

= \frac{32}{y ^{6}}

(5 x^{2} y^{3} - 11 z^{4})^{2}

\frac{13}{9} \div \frac{26}{5}

(8 - i) (\frac{4}{5} - 2 i)

- 14 - 4

- 15 - 6