What is ((-3i)^2(1-2i))/(2+2i) ?

The solution to ((-3i)^2(1-2i))/(2+2i) is 9/4+27/4 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((-3i)^2(1-2i))/(2+2i)

simplify

\frac{( - 3 i ) ^{2} ( 1 - 2 i )}{2 + 2 i}

\frac{9}{4} + \frac{27}{4} i

Solution steps

\frac{( - 3 i ) ^{2} ( 1 - 2 i )}{2 + 2 i}

Multiply by the conjugate

\frac{2 - 2 i}{2 - 2 i}

= \frac{( - 3 i ) ^{2} ( 1 - 2 i ) ( 2 - 2 i )}{( 2 + 2 i ) ( 2 - 2 i )}

Simplify

\frac{( - 3 i ) ^{2} ( 1 - 2 i ) ( 2 - 2 i )}{( 2 + 2 i ) ( 2 - 2 i )} : \frac{18 + 54 i}{8}

= \frac{18 + 54 i}{8}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{18}{8} + \frac{54}{8} i

Simplify

\frac{18}{8} + \frac{54}{8} i : \frac{9}{4} + \frac{27}{4} i

= \frac{9}{4} + \frac{27}{4} i

10 (m + 4 n)

- 10 - (- 7)

(- 4 x^{2} - 8 x) + (- x^{2} - 6 x + 8)

1 \frac{2}{5} - (- 3 \frac{3}{4})

(x + 3) (2 x - 7)

What is ((-3i)^2(1-2i))/(2+2i) ?
The solution to ((-3i)^2(1-2i))/(2+2i) is 9/4+27/4 i