What are the solutions to the equation x^2+10x+12=2x+5 ?

The solutions to the equation x^2+10x+12=2x+5 are x=-1,x=-7

Find the zeros of x^2+10x+12=2x+5

The zeros of x^2+10x+12=2x+5 are x=-1,x=-7

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x^{2} + 10 x + 12 = 2 x + 5

x = - 1, x = - 7

Solution steps

x^{2} + 10 x + 12 = 2 x + 5

Move

5

to the left side

x^{2} + 10 x + 7 = 2 x

Move

2 x

to the left side

x^{2} + 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 7 = 6

x_{1, 2} = \frac{- 8 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 6}{2 \cdot 1}, x_{2} = \frac{- 8 - 6}{2 \cdot 1}

x = \frac{- 8 + 6}{2 \cdot 1} : - 1

x = \frac{- 8 - 6}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 1, x = - 7

- 3 \cdot - 15

9 w - 4 \geq 7 + 11 w

- x^{3} + 7 x^{2} - 14 x + 8

\frac{80}{49}

2 (\frac{1}{3})^{2}

What are the solutions to the equation x^2+10x+12=2x+5 ?
The solutions to the equation x^2+10x+12=2x+5 are x=-1,x=-7
Find the zeros of x^2+10x+12=2x+5
The zeros of x^2+10x+12=2x+5 are x=-1,x=-7