What is expand (3x-5)(x+2)(x+1) ?

The solution to expand (3x-5)(x+2)(x+1) is 3x^3+4x^2-9x-10

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expand (3x-5)(x+2)(x+1)

expand

(3 x - 5) (x + 2) (x + 1)

3 x^{3} + 4 x^{2} - 9 x - 10

Solution steps

(3 x - 5) (x + 2) (x + 1)

Expand

(3 x - 5) (x + 2) (x + 1) : (3 x^{2} + x - 10) (x + 1)

= (3 x^{2} + x - 10) (x + 1)

Distribute parentheses

= 3 x^{2} x + 3 x^{2} \cdot 1 + xx + x \cdot 1 - 10 x - 10 \cdot 1

Simplify

3 x^{2} x + 3 x^{2} \cdot 1 + xx + x \cdot 1 - 10 x - 10 \cdot 1 : 3 x^{3} + 4 x^{2} - 9 x - 10

= 3 x^{3} + 4 x^{2} - 9 x - 10

(3 x^{3} + y^{2})^{2}

38 \cdot (- 410)

\frac{3 15}{6 80}

\frac{2 x - 1}{x + 4} - 1

\frac{5}{9} \div \frac{10}{7}

What is expand (3x-5)(x+2)(x+1) ?
The solution to expand (3x-5)(x+2)(x+1) is 3x^3+4x^2-9x-10