What is 1/(1+4i)+1/(1+8i) ?

The solution to 1/(1+4i)+1/(1+8i) is 82/1105-396/1105 i

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simplify 1/(1+4i)+1/(1+8i)

simplify

\frac{1}{1 + 4 i} + \frac{1}{1 + 8 i}

\frac{82}{1105} - \frac{396}{1105} i

Solution steps

\frac{1}{1 + 4 i} + \frac{1}{1 + 8 i}

\frac{1}{1 + 4 i} = \frac{1 - 4 i}{17}

\frac{1}{1 + 8 i} = \frac{1 - 8 i}{65}

= \frac{1 - 4 i}{17} + \frac{1 - 8 i}{65}

Join

\frac{1 - 4 i}{17} + \frac{1 - 8 i}{65} : \frac{- 396 i + 82}{1105}

= \frac{- 396 i + 82}{1105}

Rewrite in standard complex form:

\frac{82}{1105} - \frac{396}{1105} i

= \frac{82}{1105} - \frac{396}{1105} i

6 72 x^{2}

lo g_{5} (64)

12 x \cdot 12 x^{5}

\frac{1}{6} + \frac{8}{15}

(4 \cdot 7)^{- 4}

What is 1/(1+4i)+1/(1+8i) ?
The solution to 1/(1+4i)+1/(1+8i) is 82/1105-396/1105 i