What is 7/((-1/x)^2-3) ?

The solution to 7/((-1/x)^2-3) is (7x^2)/(-3x^2+1)

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simplify 7/((-1/x)^2-3)

simplify

\frac{7}{( - \frac{1}{x} ) ^{2} - 3}

\frac{7 x ^{2}}{- 3 x ^{2} + 1}

Solution steps

\frac{7}{( - \frac{1}{x} ) ^{2} - 3}

Simplify

(- \frac{1}{x})^{2} - 3 : \frac{- 3 x ^{2} + 1}{x ^{2}}

= \frac{7}{\frac{- 3 x ^{2} + 1}{x ^{2}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{7 x ^{2}}{- 3 x ^{2} + 1}

(x + y - 2) (x - y + 2)

(4 x - 6 y)^{2}

(- 4) (- 12)

22 + 23

(2^{4})^{- 1}