What is 1/(sqrt(x^2-4x)) ?

The solution to 1/(sqrt(x^2-4x)) is (sqrt(x^2-4x))/(x^2-4x)

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simplify 1/(sqrt(x^2-4x))

simplify

\frac{1}{x ^{2} - 4 x}

\frac{x ^{2} - 4 x}{x ^{2} - 4 x}

Solution steps

\frac{1}{x ^{2} - 4 x}

Multiply by the conjugate

\frac{x ^{2} - 4 x}{x ^{2} - 4 x}

= \frac{1 \cdot x ^{2} - 4 x}{x ^{2} - 4 x x ^{2} - 4 x}

1 \cdot x^{2} - 4 x = x^{2} - 4 x

x^{2} - 4 x x^{2} - 4 x = x^{2} - 4 x

= \frac{x ^{2} - 4 x}{x ^{2} - 4 x}

\frac{3}{7} \cdot 9

\frac{5}{90}

\frac{2}{9} + \frac{4}{9}

4 lo g_{10} (64)

(8 x - 4 - 4 x^{2}) + (7 x^{2} - 9 x - 6)

What is 1/(sqrt(x^2-4x)) ?
The solution to 1/(sqrt(x^2-4x)) is (sqrt(x^2-4x))/(x^2-4x)