What are the solutions to the equation 2(x+4)(6+x)=0 ?

The solutions to the equation 2(x+4)(6+x)=0 are x=-4,x=-6

Find the zeros of 2(x+4)(6+x)=0

The zeros of 2(x+4)(6+x)=0 are x=-4,x=-6

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2 (x + 4) (6 + x) = 0

x = - 4, x = - 6

Solution steps

2 (x + 4) (6 + x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or 6 + x = 0

Solve

x + 4 = 0 : x = - 4

Solve

6 + x = 0 : x = - 6

The solutions to the quadratic equation are:

x = - 4, x = - 6

\frac{160}{8}

x + \frac{1}{4} x = 15

lo g_{2} (x) < \frac{1}{4} x^{2}

49 x - 98 y + 49

∣ - 3 x + 6 ∣ = 2

What are the solutions to the equation 2(x+4)(6+x)=0 ?
The solutions to the equation 2(x+4)(6+x)=0 are x=-4,x=-6
Find the zeros of 2(x+4)(6+x)=0
The zeros of 2(x+4)(6+x)=0 are x=-4,x=-6