What is (3x^{-3})^{-4}x^{-4} ?

The solution to (3x^{-3})^{-4}x^{-4} is (x^8)/(81)

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simplify (3x^{-3})^{-4}x^{-4}

simplify

(3 x^{- 3})^{- 4} x^{- 4}

\frac{x ^{8}}{81}

Solution steps

(3 x^{- 3})^{- 4} x^{- 4}

Simplify

(3 x^{- 3})^{- 4} : \frac{x ^{12}}{81}

= \frac{x ^{12}}{81} x^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 4} = \frac{1}{x ^{4}}

= \frac{x ^{12}}{81} \cdot \frac{1}{x ^{4}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x ^{12} \cdot 1}{81 x ^{4}}

Apply rule:

a \cdot 1 = a

x^{12} \cdot 1 = x^{12}

= \frac{x ^{12}}{81 x ^{4}}

Simplify

\frac{x ^{12}}{x ^{4}} : x^{8}

= \frac{x ^{8}}{81}

(8 x^{2} + 4 x + 12) + (2 x^{2} + 7 x + 10)

\frac{x ^{2} - 9 x + 20}{x ^{2} + x - 20}

27 - 7 (x - 4) + 4 (2 x - 3)

10 (0.8)^{10}

(x - 2)^{2} + 9 (x - 2) + 5

What is (3x^{-3})^{-4}x^{-4} ?
The solution to (3x^{-3})^{-4}x^{-4} is (x^8)/(81)